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Day Codes:-
- What was the day of the week on 24th July 2011?
A.) Monday B.) Sunday C.) Friday D.) None of these Answer: Option 'B'
Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (24 + 0 + 11 + 2 + 6)/7 = 43/7 = 1
= Sunday - What was day of the week on 21-September-1987?
A.) Sunday B.) Monday C.) Friday D.) Saturday Answer: Option 'B'
Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (21 + 6 + 87 + 21 + 0)/7 = 135/7 = 2
= Monday - What was the day of the week on 26-January-1950?
A.) Sunday B.) Monday C.) Wednesday D.) Thursday Answer: Option 'D'
Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7
= (26 + 1 + 50 + 12 + 0)/7 = 84/7 = 5
= Thursday - Today is Monday, after 61 days, the day will be:
A.) Wednesday B.) Saturday C.) Tuesday D.) Thursday Answer: Option 'B'
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be saturday. - Which of the following is not a leap year?
A.) 700 B.) 800 C.) 1200 D.) 2000 Answer: Option 'A'
The century divisible by 400 is a leap year.
The tear 700 is not a leap year - 6. Today is Friday, after 126 days, it will be:
A.) Sunday B.) Tuesday C.) Friday D.) Monday Answer: Option 'C'
126/7 = 0
Each day of the week is repeated after 7 days.
So, after 126 days, it will be Friday.
After 126 days, it will be Friday. - 7. How many days are there in x weeks X days?
A.) 7x² B.) 8x C.) 14x D.) 7 Answer: Option 'B'
x weeks x days = (7x + x) days = 8x days - 8. It was Sunday on January-1-2006. Find the day of the week on
January-1-2010?
A.) Sunday B.) Saturday C.) Friday D.) Wednesday Answer: Option 'C'
On 31st December, 2005 it was Saturday.
Number of odd days from the year 200 to the tear 2009 = ( 1 + 1 + 2 + 1 ) = 5days
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday. - 9. What was the day of the week on 7th October, 2003?
A.) Sunday B.) Saturday C.) Friday D.) Wednesday Answer: Option 'B'
Formula = ( Date + Monthcode + No.of years + No.of leapyears + Century code )/ 7
==> (7 + 1 + 3 + 0 + 6)/7 = 17/7 = 3
==> Tuesday - 10. On 2007, What was the date of last Saturday in May month?
A.) 21 B.) 22 C.) 25 D.) 26 Answer: Option 'D'
1 - May - 2007
=(1 + 2 + 7 + 1 + 6)/7 = 17/7 = 3 = Tuesday
= May 1st --> Tuesday + 5 days = Saturday = 5th may
5th may + 7 days = Saturday = 12th may 12th may + 7 days = Saturday = 19th may 19th may + 7 days = Saturday = 26th may = Answer = 26th may
- 11. What was the day of the week on 10th March 1996?
A.) Sunday B.) Tuesday C.) Saturday D.) Wednesday Answer: Option 'A'
(10 + 4 + 96 + 24 + 0)/7 = 134/7 = 1
= Sunday
- 12. On 8th February 2005, it was Tuesday. What was the day of the week
on 8 February 2004?
A.) Tuesday B.) Monday C.) Sunday D.) Wednesday Answer: Option 'C'
The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005
Hence, this day is Sunday.
- 13. What was the day of the week on 17th June, 1998
A.) Tuesday B.) Monday C.) Sunday D.) Wednesday Answer: Option 'D'
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 × 3) = 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years = (24 × 2 + 73) = 121 = 2 odd days
Jan Feb March April May June
31 + 28 + 31 + 30 + 31 + 17 = 168 days = 24 weeks = 0 odd day
Total number of odd days = (0 + 1 + 2 + 0) = 3
Given day is Wednesday
Sat = 0
Sun = 1
Mon = 2
Tue = 3
Wed = 4
Thu = 5
Fri = 6
Month Codes:-
Jan = 1
Feb = 4
Mar = 4
Apr = 0
May = 2
Jun = 5
Jul = 0
Aug = 3
Sep = 6
Oct = 1
Nov = 4
Dec = 6
Century Codes:-
1500 - 1599 ---> 0
1600 - 1699 ---> 6
1700 - 1799 ---> 4
1800 - 1899 ---> 2
1900 - 1999 ---> 0
2000 - 2099 ---> 6
2100 - 2199 ---> 4
2200 - 2299 ---> 2
2300 - 2399 ---> 0
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